[CPUFREQ] Disambiguate loop indexes in powernow-k7
authorDave Jones <davej@redhat.com>
Tue, 30 May 2006 21:26:08 +0000 (17:26 -0400)
committerDave Jones <davej@redhat.com>
Tue, 30 May 2006 21:26:08 +0000 (17:26 -0400)
This shouldn't have actually caused any problems
(as we return if we 'corrupt' 'i', but it's still not
very pretty.  For the sake of adding another local variable,
this got cleaner.

Signed-off-by: Dave Jones <davej@redhat.com>
arch/i386/kernel/cpu/cpufreq/powernow-k7.c

index 2bf4237cb94ea85e8bd3d39ee4242643e1fdf3b8..5d2b601425b83fe6157edaa010eec41f0e0920a5 100644 (file)
@@ -452,23 +452,23 @@ static int powernow_decode_bios (int maxfid, int startvid)
 
                        pst = (struct pst_s *) p;
 
-                       for (i = 0 ; i <psb->numpst; i++) {
+                       for (j=0; j<psb->numpst; j++) {
                                pst = (struct pst_s *) p;
                                number_scales = pst->numpstates;
 
                                if ((etuple == pst->cpuid) && check_fsb(pst->fsbspeed) &&
                                    (maxfid==pst->maxfid) && (startvid==pst->startvid))
                                {
-                                       dprintk ("PST:%d (@%p)\n", i, pst);
+                                       dprintk ("PST:%d (@%p)\n", j, pst);
                                        dprintk (" cpuid: 0x%x  fsb: %d  maxFID: 0x%x  startvid: 0x%x\n",
                                                 pst->cpuid, pst->fsbspeed, pst->maxfid, pst->startvid);
 
                                        ret = get_ranges ((char *) pst + sizeof (struct pst_s));
                                        return ret;
-
                                } else {
+                                       unsigned int k;
                                        p = (char *) pst + sizeof (struct pst_s);
-                                       for (j=0 ; j < number_scales; j++)
+                                       for (k=0; k<number_scales; k++)
                                                p+=2;
                                }
                        }